C3H5(OH)3 + O2 = CO2 + H20 – Chemical Equation Balancer

Balanced Chemical Equation

10C3H5(OH)3 + 15O2 → 30CO2 + 4H20

Warning: Some of the compounds in the equation are unrecognized. Verify it is entered correctly.

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Reaction Information Disclaimer

C3H5(OH)3+O2=CO2+H20

Reaction Type

Single Displacement (Substitution)

Reactants

• Glycerol – C3H5(OH)3

  Ifp Gro Rg-S E 422 Glyrol Bulbold Cristal Glycerin C3H5(OH)3 Molar Mass C3H5(OH)3 Oxidation Number

• Dioxygen – O2

  Lox O₂ Oxygen Oxygen Gas Liquid Oxygen Triplet Oxygen Diatomic Oxygen Molecular Oxygen O2 Molar Mass O2 Bond Polarity O2 Oxidation Number

Products

• Carbon Dioxide – CO2

  Co2 E290 Co₂ E 290 E-290 R-744 [Co2] Dry Ice CO2 Molar Mass CO2 Oxidation Number

• H20

Calculate Reaction Stoichiometry Calculate Limiting Reagent

Use the calculator below to balance chemical equations and determine the type of reaction (instructions).

🛠️ Equation Editor Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above. Information about the equation, such as the type of reaction may also be calculated.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

Examples

• C3H5(OH)3 + O2 = C + H2O
• C3H5(OH)3 + O2 = C3H5O2 + H2O
• C3H5(OH)3 + O2 = C3H6O3 + H2O
• C3H5(OH)3 + O2 = CHO + H2O
• C3H5(OH)3 + O2 = CO + H20
• C3H5(OH)3 + O2 = CO + H2O
• C3H5(OH)3 + O2 = CO(COOH)2 + H2
• C3H5(OH)3 + O2 = CO2 + H2O
• C3H5(OH)3 + O2 = CO2 + HOH
• C3H5(OH)3 + O2 = H2O + CO2
• CO2 + H20 + F2 = CH2F2 + O2
• CO2 + H20 + N2 = C2H7NO + O2
• Recently Balanced Equations

How To Balance Equations

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How To Balance C3H5(OH)3 + O2 = CO2 + H20

• Algebraic Method
• Using Inspection

Balance the equation C3H5(OH)3 + O2 = CO2 + H20 using the algebraic method or linear algebra with steps.

1. Label Each Compound With a Variable

   Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

   a C3H5(OH)3 + b O2 = c CO2 + d H20

2. Create a System of Equations

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   Create an equation for each element (C, H, O) where each term represents the number of atoms of the element in each reactant or product.

   C: 3a + 0b = 1c + 0d H: 8a + 0b = 0c + 20d O: 3a + 2b = 2c + 0d

3. Solve For All Variables

   Use substitution, Gaussian elimination, or a calculator to solve for each variable.

   Using Substitution or Elimination

   • 3a – 1c = 0
   • 8a – 20d = 0
   • 3a + 2b – 2c = 0

   Using Linear Systems / Algebra

   Use your graphing calculator’s rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

   [ 3 0 -1 0 0] [ 8 0 0 -20 0] [ 3 2 -2 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

   Simplify the result to get the lowest, whole integer values.

   • a = 10 (C3H5(OH)3)
   • b = 15 (O2)
   • c = 30 (CO2)
   • d = 4 (H20)

4. Substitute Coefficients and Verify Result

   Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

   10 C3H5(OH)3 + 15 O2 = 30 CO2 + 4 H20Reactants Products C3030✔️H8080✔️O6060✔️Since there is an equal number of each element in the reactants and products of 10C3H5(OH)3 + 15O2 = 30CO2 + 4H20, the equation is balanced.

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Balance C3H5(OH)3 + O2 = CO2 + H20 by inspection or trial and error with steps.

The law of conservation of mass says that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To balance a chemical equation, every element must have the same number of atoms on each side of the equation.

1. Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)C3H5(OH)3O2TotalCO2H20TotalC3311❌H882020❌O32522❌

2. Multiply coefficients for compounds to balance out each element

1. C is not balanced. Add 2 molecule(s) of CO2 to the product (right-hand) side to balance Carbon: C3H5(OH)3 + O2 = 3CO2 + H20ReactantsProductsC33✔️H820❌O56❌

We could not determine all the steps needed to balance the equation using trial and error. This may mean it requires too many steps and the chemical equation is too complex to use this method, or that the equation is invalid (e.g. has 0 or non-integer coefficients). The algebraic method is likely better suited for balancing this equation.

If you would like to attempt to guess the next steps, the final element counts in the balanced equation should be:

10C3H5(OH)3 + 15O2 = 30CO2 + 4H20

ReactantsProductsC3030✔️H8080✔️O6060✔️